Challenge – MaTH !

Who knows how to resolve this, has an award. Seriously, who can resolve this, will get an award which he/she will put on his/her blog 🙂 !
a) Show that if a natural number has only three divisors, it is the square of a prime number
b) Show that if a natural number has only four divisors, it is the cube of a prime number or the product of two prime numbers.

Try 🙂

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4 thoughts on “Challenge – MaTH !

  1. Thanks for visiting my site..now as per your maths question the answer to the a) part is 49 which is the square of 7 and 7 is a prime number and 49 has only 3 divisors they are 1,7,49
    the answer to the b) part of your questn is 35 as it has 4 divisors 1,5,7,35 and 35 is made up of two prime numbers they are 5&7..

    • Hi ! Welcome 😉 ! Your response is for an exercise like “write a number which nuber is … (has that propriety)”. Your solution must be on general caze !
      Good luck 😉 !
      Riic

    • Thank you :), but the solution must be on general caze. You must to demonstate that every natural number which is prime and … has this property !

      Good luck 😉 !
      Riic

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